A box holds 4 red and 6 blue markers that are identical except for color. Two markers are drawn at random without replacement. What is the probability that both are red?
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Answer: D
4/25: 4/25 = (4/10)(4/10) assumes replacement. Without replacement, the second draw is 3 red out of 9.
2/5: 2/5 is the probability that a single draw is red. It ignores the second draw.
11/15: This adds the probabilities (4/10 + 3/9). For two events that must both happen, multiply.
2/15: Correct. P = (4/10) x (3/9) = 12/90 = 2/15.
For "both A and B," multiply. Without replacement, reduce both the favorable count and the total for the second draw.