EEI TOSS Practice Questions (2026) — Free Sample Questions with Answers

Answer: C

1. 1. Height = base + middle + top − overlaps
2. 2. 32 = 12 + 12 + X − 1 − 1 = 22 + X
3. 3. X = 32 − 22 = 10′

8′: Ignored both 1′ overlaps: 32 − 12 − 12 = 8′.

9′: Allowed for only one of the two 1′ overlaps.

10′: Correct. Overlaps hide 1′ at each of the two splices, so the sections add to 2′ more than the height: 12 + 12 + X − 1 − 1 = 32, so X = 10′.

12′: Added each 1′ overlap back twice (32 − 24 + 4).

Where parts overlap, the overall length is the sum of the parts minus every overlap; add the overlaps back when working out a missing part.

Answer: D

1. 1. Pipes: 4 × 4″ = 16″
2. 2. Gaps between 4 pipes: 3 × 3″ = 9″
3. 3. W = 16 + 9 = 25″

16″: Added the four 4″ pipes but left out the gaps.

21″: This is the center-to-center distance from the first pipe to the last, which leaves out half a pipe at each end.

22″: Counted only two 3″ gaps between four pipes.

25″: Correct. Four 4″ pipes and the three 3″ gaps between them: W = 4 × 4 + 3 × 3 = 16 + 9 = 25″.

An outside-to-outside width counts every part in full plus the gaps between them.

Answer: C

1. 1. Feet: 3 + 12 + 4 = 19′
2. 2. Inches: 8 + 6 + 10 = 24″ = 2′-0″
3. 3. L = 19′ + 2′ = 21′-0″

19′-0″: Added the feet and dropped the 24″ that the inches add up to.

20′-0″: Carried only 1′ for the 24″; 24″ is 2′.

21′-0″: Correct. Feet: 3 + 12 + 4 = 19′; inches: 8 + 6 + 10 = 24″ = 2′; L = 19′ + 2′ = 21′-0″.

21′-4″: Treated 24″ as 2′-4″, as if a foot had 10 inches.

Add feet and inches separately, then convert every 12 inches into a foot.

Answer: B

1. 1. Overall rectangle: 10 × 8 = 80 square inches
2. 2. Notch: 4 × 5 = 20 square inches
3. 3. Area = 80 − 20 = 60 square inches

36 sq in: This is the perimeter, 2 × (10 + 8), not the area.

60 sq in: Correct. The full 10″ × 8″ rectangle is 80 square inches; the 4″ × 5″ notch is missing: 80 − 20 = 60 square inches.

70 sq in: Took the notch as a triangle (½ × 4 × 5 = 10) instead of a rectangle.

80 sq in: Used the overall 10″ × 8″ rectangle without removing the notch.

Find the area of an L shape as the enclosing rectangle minus the missing corner rectangle.

Answer: C

1. 1. Aerial cut east of SC1: SC1 and its south branch to FDH-6 stay connected; SC7, SC2, SC3 and FDH-1, -2, -3 are cut off.
2. 2. Underground cut south of SC4: SC4 and its west branch to FDH-5 stay connected; SC5, SC6, FDH-4 and FDH-7 are cut off.
3. 3. Cabinets with service: FDH-5 and FDH-6 = 2.

0: Treated SC1 and SC4 as cut off too; both are on the CO side of the cuts, so their branches still work.

1: Kept only one of the two surviving branches: FDH-6 (south from SC1) and FDH-5 (west from SC4) both keep service.

2: Correct. West of the aerial cut, SC1 still feeds FDH-6; north of the underground cut, SC4 still feeds FDH-5. FDH-1, -2, -3, -4 and -7 lose their only path.

3: Assumed one of the cabinets beyond a cut, such as FDH-7, could be reached another way; this route map has no loops.

On a branching (tree) route, a cut removes everything beyond it but leaves branches that leave the route before the cut.

Answer: D

B1: B1 holds the CO, where the aerial cable starts; the cabinet is at the end of the branch running south from SC1.

B2: B2 holds SC4 on the underground cable; the cabinet that SC4 feeds (FDH-5) is in A2.

C1: C1 holds SC1 itself, where the branch starts, not the cabinet at its end.

C2: Correct. The solid line from SC1 runs straight down to FDH-6, which sits in row 2 of column C.

Follow the named cable from its starting symbol to its end before reading the sector.

Answer: A

1. 1. The underground cable is the dashed line leaving the bottom of the CO.
2. 2. Splice cases on it: SC4, SC5, SC6.
3. 3. SC1, SC2, SC3 and SC7 are on solid (aerial) lines. Total: 3.

3: Correct. SC4, SC5 and SC6 sit on the dashed underground cable; the other four splice cases are on the aerial cable.

4: Also counted SC1, which is on the solid aerial cable just east of the CO, not on the underground cable.

5: Counted two of the underground cabinets (open squares) as splice cases.

6: Counted all three underground cabinets, FDH-4, FDH-5 and FDH-7, as splice cases.

Count by the line style that runs through each symbol.

Answer: B

1. 1. C1 is column C, row 1.
2. 2. Filled circles there: SC1 and SC7.
3. 3. SC2 lies just past the C/D line, in D1. Total: 2.

1: Missed SC1, which sits just east of the B/C boundary and is therefore in C1.

2: Correct. SC1 (just east of the B/C line) and SC7 are the two filled circles on the aerial cable in C1.

3: Also counted SC2, which is just east of the C/D boundary in D1.

4: Counted SC2 and the CO building as well; the CO is in B1 and SC2 is in D1.

Check each symbol near a boundary against the sector lines before counting it.

Answer: C

1. 1. Cart X: 150 lb × 4 ft/s = 600, to the right.
2. 2. Cart Y: 200 lb × 3 ft/s = 600, to the left.
3. 3. 600 − 600 = 0, so the coupled carts do not move.

Direction A: Chose the faster cart's direction; Cart X is faster but lighter, so its momentum is no larger than Cart Y's.

Direction B: Chose the heavier cart's direction; Cart Y is heavier but slower, so its momentum is no larger than Cart X's.

The carts stop: Correct. Momentum is weight times speed. Cart X has 150 × 4 = 600 to the right and Cart Y has 200 × 3 = 600 to the left. The two are equal and opposite, so the coupled carts stop.

Compare momentum (weight × speed), not weight or speed alone; equal and opposite momenta cancel.

Answer: A

Port A: Correct. Oil entering Port A presses on the left face of the piston and pushes it away from that port, to the right, so the rod extends and closes the gate.

Port B: Oil at Port B pushes on the right face of the piston, which pulls the rod in and opens the gate.

Either port (A or B): Each port pushes the piston in only one direction, so the choice of port decides the motion.

Pressure on a piston face pushes the piston away from the port where the fluid enters.

Answer: A

Point A: Correct. The bar hangs level when the hook is directly over the centre of gravity. At A, 2 ft from the pump: 300 × 2 = 600 and 100 × 6 = 600, so the turning effects balance.

Point B: Point B is the middle of the bar. That would balance only equal loads; the heavier pump would make the left end drop.

Point C: Point C is on the side of the lighter valve, so the 300 lb pump would swing the left end down even harder.

A load hangs level only when the lift point is directly above its centre of gravity, which lies closer to the heavier end.

Answer: B

Hook A: Hook A holds only the rope’s end. With two segments on the movable pulley, the rope tension is 60 lb, so hook A carries 60 lb.

Hook B: Correct. The rope tension is 120 ÷ 2 = 60 lb. Hook A holds one rope end (60 lb). Hook B’s pulley has the rope pulling down on both sides, 60 lb toward the load and 60 lb toward the worker, so hook B carries 120 lb.

Both hooks carry the same load: Hook A takes one rope segment, but hook B’s pulley takes two (the segment from the load and the worker’s pull), so B carries twice as much.

A fixed pulley’s support carries the rope tension once for every rope run pulling on it, including the run the worker pulls.

Answer: C

1. 1. Rule 1: not stock → no.
2. 2. Rule 2, first branch: needed in 3 days, which is 3 or fewer → Reviewer 3.

Reviewer 1: Reviewer 1 is for stock items costing $2,000 or less.

Reviewer 2: Applied the cost branch, which also requires more than 3 days; this material is needed in exactly 3 days.

Reviewer 3: Correct. Rule 2 covers non-stock items, and "3 days or fewer" includes 3 days, so the first branch sends it to Reviewer 3. The cost is not tested by that branch.

Reviewer 4: Applied the default rule although Rule 2's first branch fits.

"Or fewer" includes the boundary value; check the boundary before moving to the next branch.

Answer: D

1. 1. Rule 1: not stock → no.
2. 2. Rule 2, first branch: 7 days is not 3 or fewer → no.
3. 3. Rule 2, second branch: more than 3 days, yes; over $2,000, no → no.
4. 4. Rule 3 → Reviewer 4.

Reviewer 1: Reviewer 1 is for stock items only.

Reviewer 2: The second non-stock branch needs a total over $2,000; this request is $1,500.

Reviewer 3: Reviewer 3 needs the material in 3 days or fewer; it is needed in 7 days.

Reviewer 4: Correct. Rule 2 covers non-stock items, but 7 days fails the first branch and $1,500 fails the second, so Rule 3 sends it to Reviewer 4.

Both conditions of a two-condition branch must be met; one miss sends the case on to the default.

Answer: A

1. 1. Rule 1 (stock), first branch: $850 ≤ $2,000 → Reviewer 1.

Reviewer 1: Correct. Rule 1 covers stock items, and $850 is $2,000 or less, so Reviewer 1. The delivery time is tested only for non-stock items.

Reviewer 2: Reviewer 2 takes stock requests only when they cost over $2,000.

Reviewer 3: Reviewer 3 is for non-stock items needed in 3 days or fewer.

Reviewer 4: Applied the default rule although Rule 1 assigns this request.

Identify the item category first; each rule tests only its own conditions.