GA Milestones EOG Practice Questions (2026) — Free Sample Questions with Answers

Answer: A

Passage 1 treats it as a cause of brighter skies, while Passage 2 treats it as a success that taught lessons.: Correct. Passage 1 says LEDs "made the problem worse in some places"; Passage 2 calls the switch "one of the clearest successes" and notes the lessons learned about glare.

Passage 1 says LEDs waste energy, while Passage 2 says LEDs save energy and money for cities.: Passage 1 also says "LEDs save energy"; the authors agree on energy and differ on how to judge the result.

Passage 1 says LEDs harm sea turtles, while Passage 2 says LEDs protect birds that migrate at night.: Neither passage connects LEDs to sea turtles or claims that LEDs protect birds.

Passage 1 calls the switch a complete failure, while Passage 2 says no changes to LEDs are needed.: Both claims are too extreme: Passage 1 says "in some places," and Passage 2 describes changes such as warmer LEDs.

Two authors can accept the same facts and still interpret them differently; compare the judgment each one draws.

Answer: D

It introduces a new main idea about how tardigrades could be useful in medicine.: The medical use is introduced in paragraph 7, not paragraph 6.

It shows that the experiments described in paragraph 4 were poorly designed.: Paragraph 6 never questions how the experiments were done; it explains that survival depends on the tun state.

It explains the steps a tardigrade follows to form a tun as its habitat dries.: The tun is described in paragraph 3; paragraph 6 mentions drying only to explain a limit.

It qualifies the earlier picture of tardigrade toughness by showing its limits.: Correct. After paragraphs 3–5 describe amazing survival, paragraph 6 explains that active tardigrades are delicate and that even tuns often die, so the toughness "belongs to one special state."

Expository writers often follow impressive evidence with a qualifying section; ask how a paragraph changes or limits what came before it.

Answer: D

It retells the events of the myth in the same order as the original, changing only the names of the characters and the setting.: The story changes the outcome: Gemma is not punished, and the spider becomes something she chooses to keep.

It reverses the roles in the myth so that the older, more experienced artist is the one who shows too much pride in her work.: Gemma, the young artist, is the proud one, just like Arachne; Ms. Adeyemi stays calm.

It uses the myth to show that a gifted young person's pride will always be punished in the end, just as Arachne's was.: Gemma is never punished; the story replaces punishment with a chance to change.

It keeps the myth's proud student and her challenge to an elder but turns the spider into an invitation to change.: Correct. Like Arachne, Gemma claims no one taught her and mocks her teacher in her art, but the spider "felt more like a question" (paragraph 10), and Gemma answers it by changing the mural.

When a modern story draws on a myth, look for what it keeps (character types, event patterns) and what it changes (outcome, meaning).

Answer: A

It explains the meaning behind the bell and the knot saying, which helps Hana understand her grandfather at the end.: Correct. The flashback shows where the bell ritual and "you can always untie it" came from, so the reader sees why Hana accepts "Like a good knot" in paragraph 9 and ties a knot that is "easy to loosen."

It creates suspense about whether Hana will be hurt again when she walks out alone to the very end of the dock.: The flashback tells events that are already over and ended safely, so it does not build suspense about her safety.

It shows that Hana is still afraid of the water and explains why she wants so badly for the shop to stay open.: The flashback ends with Hana at the end of the dock with her feet in the water, so her fear is in the past.

It reveals that the grandfather once planned to leave the shop to Hana when he finally retired from fishing.: Nothing in the flashback mentions plans for the shop's future; this is an inference the text does not support.

A flashback's purpose is judged by how its past events connect to the present conflict and its resolution.

Answer: (1) were, (2) practice

The subjunctive mood uses "were" for unreal conditions and the base form of the verb after verbs such as suggest, recommend, and insist.

Answer: A

The period would use only forty minutes a week, and nearby schools with club periods have seen no drop in scores.: Correct. It answers the worry about lost class time directly, with a small time cost and evidence that scores did not fall.

Testing is stressful for students and teachers alike, and many students worry about their scores all spring.: This adds to the testing concern instead of answering it.

Many teachers already give up their own free time to coach sports teams and to tutor students after school.: This praises teachers but does not respond to the concern about class time.

Students in clubs build teamwork, confidence, and patience, as the examples in the second paragraph show.: This repeats a reason for the claim but does not address the counterclaim about instruction time.

A rebuttal must answer the specific concern raised in the counterclaim, ideally with a reason or evidence.

Answer: C

1. 1. $6.76<7<7.29$, so $2.6<\sqrt{7}<2.7$.
2. 2. The rounding boundary is 2.65: $2.65^2=7.0225$.
3. 3. $7<7.0225$, so $\sqrt{7}<2.65$.
4. 4. Therefore $\sqrt{7}\approx 2.6$ to the nearest tenth.

$\sqrt{7}\approx 2.7$, because 7 lies between 6.76 and 7.29 and 2.7 is the greater bound: Being between the two squares shows only that the root is between 2.6 and 2.7; it does not decide which tenth is closer.

$\sqrt{7}\approx 2.7$, because $2.65^2=6.9225$, which is less than 7: Squares 2.65 incorrectly; $2.65^2=7.0225$, not 6.9225.

$\sqrt{7}\approx 2.6$, because $2.65^2=7.0225$, which is greater than 7: Correct. The halfway value 2.65 squared is 7.0225, which is more than 7, so $\sqrt{7}$ is less than 2.65 and rounds to 2.6. (A calculator confirms $\sqrt{7}\approx 2.646$.)

$\sqrt{7}\approx 2.6$, because $2.6^2$ is less than 7: The conclusion is right but the reason is not: $2.6^2<7$ is also true of $\sqrt{7.2}$, which rounds to 2.7. Only comparing 7 with $2.65^2$ settles the rounding.

To round a square root to the nearest tenth, square the halfway value (such as 2.65) and compare it with the radicand.

Answer: a table with the pairs (1, 4), (2, 7) and (3, 10): Non-proportional; y=34x: Proportional; the line through (−2, 5) and (4, −10): Proportional; the cost of renting a kayak at $12 per hour, with no other fees: Proportional; y=3x+0.5: Non-proportional

A linear relationship is proportional only when it can be written y = mx, so its graph passes through the origin; any nonzero b makes it non-proportional.

Answer: 66 shirts

1. 1. Profit: $15s-(90+6s)=9s-90$.
2. 2. Solve $9s-90\ge 500$: $9s\ge 590$, so $s\ge 65.\overline{5}$.
3. 3. Shirts come in whole numbers, so the least value is 66.
4. 4. Check: 66 shirts give $9(66)-90=504\ge 500$; 65 shirts give $9(65)-90=495<500$.

When the variable counts whole objects, round a decimal boundary in the direction that keeps the inequality true (up, for "at least").

Answer: C

1. 1. Set the expressions equal: $2x-1=-x+4$.
2. 2. $3x=5$, so $x=\frac{5}{3}\approx 1.67$.
3. 3. $y=-\frac{5}{3}+4=\frac{7}{3}\approx 2.33$.
4. 4. Check in the other equation: $2\left(\frac{5}{3}\right)-1=\frac{10}{3}-\frac{3}{3}=\frac{7}{3}$.

The solution is (2, 3), because that is the grid point nearest to where the lines cross.: (2, 3) is on $y=2x-1$, but $-2+4=2$, not 3, so it is not on the other line.

The system has no solution, because the lines do not cross at a grid point.: Lines with different slopes (2 and −1) always cross exactly once, whether or not at a grid point.

The solution is exactly $\left(\frac{5}{3},\frac{7}{3}\right)$, which a graph shows as about (1.7, 2.3).: Correct. $2x-1=-x+4$ gives $3x=5$, so $x=\frac{5}{3}$ and $y=2\left(\frac{5}{3}\right)-1=\frac{7}{3}$; a graph can only estimate this as about (1.7, 2.3).

The solution is exactly (1.7, 2.3), because that is where the graph shows the lines crossing.: (1.7, 2.3) is a rounded estimate: $2(1.7)-1=2.4$, not 2.3. The exact solution is $\left(\frac{5}{3},\frac{7}{3}\right)$.

A graph gives an estimate of a solution; solve algebraically to find the exact intersection, and check it in both equations.

Answer: C

Each bicycle loses exactly $37.50 in value every year.: Treats the model as exact for every bicycle; the points are scattered around the line, so the slope describes a tendency.

A bicycle that is 0 years old is predicted to sell for about $450.: This describes the y-intercept, 450, not the slope.

Each additional year of age is associated with a price about $37.50 lower.: Correct. The slope, $-37.5$ dollars per year, means that, on average in these data, each extra year of age goes with a price about $37.50 lower.

Each additional year of age is associated with a price about $450 lower.: Uses the y-intercept as the rate of change.

The slope of a line of fit is the predicted change in y for each 1-unit increase in x, described as an association ("is associated with"), not an exact rule.

Answer: A

Line 2, because it follows the trend and has about as many points above it as below it: Correct. Line 2 runs through the middle of the cloud: 7 points lie above it and 5 below, all fairly close to it.

Line 1, because it passes exactly through two of the data points: Passing through data points does not make a good fit; the other 10 points all lie below Line 1.

Line 1, because every data point lies on it or below it: Having all the points on one side is the sign of a poor fit; a line of fit should split the points roughly evenly.

Neither line, because a line of fit must pass through both the first and the last data points: A line of fit does not have to pass through any particular point; it is placed to follow the overall pattern.

A good line of fit follows the direction of the data with the points close to it and roughly balanced above and below; it need not pass through any data point.

Answer: 11 dollars

1. 1. Nadia's rule: rate 12 per week, initial value 45, so $y=12x+45$.
2. 2. Nadia at 12 weeks: $12(12)+45=189$.
3. 3. Quentin at 12 weeks: $15(12)+20=200$.
4. 4. $200-189=11$.
5. 5. Check Nadia's rule against the table: $12(8)+45=141$.

Write each function as y = mx + b using its rate of change and initial value, then evaluate both at the same input.